If K_(sp) for HgSO_(4) is 6.4xx10^(-5) , then solubility of this substance in mole per m^(3) is
STATEMENT-1 : In the given reaction, NaOH+H_(3)PO_(4)rarr NaH_(2)PO_(4)+H_(2)O equivalent mass of H_(3)PO_(4) is M//3 STATEMENT-2 : H_(3)PO_(4) is tribasic acid.
K_(sp) of AgCl is 1xx10^(-10) . Its solubility in 0.1 M KNO_(3) will be :
Phospheric acid (H_(3)PO_(4)) perpared in two step process . (1) P_(4)+5O_(2) to P_(4)O_(10)" "(2) P_(4)O_(10) + 6H_(2)O to 4H_(3)PO_(4) Well allow 62 g of phosphrous to react with exces oxygen which from P_(4)O_(10) in 85% yield . In the sep (2) reaction 90% yield of H_3)PO_(4) is obtained . Mass of H_(3) PO_(4) produced is :
A solution is 0.10 M Ba(NO_(3))_(2) and 0.10 M Sr(NO_(3))_(2.) If solid Na_(2)CrO_(4) is added to the solution, what is [Ba^(2+)] when SrCrO_(4) begins to precipitate? [K_(sp)(BaCrO_(4))=1.2xx10^(-10),K_(sp)(SrCrO_(4))=3.5xx10^(-5)]
The solubility of different springly soluble salts are given as under : {:(S. No,"Formula Type","Solubility product"),((1),"AB" ,4.0xx10^(-20)),((2),A_(2)B,3.2xx10^(-11)),((3),AB_(3),2.7xx10^(-31)):} The correct increasing order of solubility is :
A saturated solution of Ca_(3)(PO_(4))_(2) has [Ca^(2+)]=2xx10^(-8) M and [PO_(4)^(3-)]=1.6xx10^(-5) M K_(sp) of Ca_(3)(PO_(4))_(2) is :
The solubility of Ba_(3)(AsO_(4))_(2) (formula mass=690) is 6.9xx10^(-2) g//100 mL. What is the K_(sp) ?
AgBr (s) + 2S_(2)O_(3)^(2)(aq.)hArrAg(S_(2)O_(3))_(2)^(3-)(aq.)+Br^(-)(aq) "[""Using":K_(sp)(AgBr)=5xx10^(-13)" " K_(f)(Ag(S_(2)O_(3))_(2)^(3-))=5xx10^(13)"]" What is the molar solubility of AgBr in 0.1 M Na_(2)SO_(3) ?
NARENDRA AWASTHI-IONIC EEQUILIBRIUM-Assertin-Reason Type Questions
