Home
Class 11
CHEMISTRY
The solubility of PbF(2) (formula mass =...

The solubility of `PbF_(2)` (formula mass =245) is 0.46 g/L. What is the solubility product?

A

`1.1xx10^(-10)`

B

`2.6xx10^(-8)`

C

`1.1xx10^(-7)`

D

`6.8xx10^(9)`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • IONIC EEQUILIBRIUM

    NARENDRA AWASTHI|Exercise Level- 1|1 Videos

  • IONIC EEQUILIBRIUM

    NARENDRA AWASTHI|Exercise Level- 2|10 Videos

  • GASEOUS STATE

    NARENDRA AWASTHI|Exercise Level 3 - Subjective Problems|1 Videos

  • SOLID STATE

    NARENDRA AWASTHI|Exercise Level 3 - Subjective Problems|1 Videos

Similar Questions

Explore conceptually related problems

What is the solubility of a substance ?

The solubility of AgBrO_(3) (formula mass=236) is 0.0072 g in 1000 mL. What is the K_(sp) ?

The solubility of Ba_(3)(AsO_(4))_(2) (formula mass=690) is 6.9xx10^(-2) g//100 mL. What is the K_(sp) ?

Solubility of Ag_(2)CrO_(4) is 8 xx 10^(-5) mol L^(-1) . Calculate the solubility product.

Briefly explain the terms Solubility product.

Define solubility product of a salt.

Determine the molar solubility of MgF_(2) from its solubility product K_(sp)=4xx10^(-9) :