At 90^(@) C, pure water has [H^(+)]=10^(-6) M.If 100 mL of 0.2 M HCl is added to 200 mL of 0.1 M KOH at 90^(@) C then pH of the resulting solution will be :
100mL of 10% NaOH(w/V) is added to 100 mL of 10% HCI(w/V) . The nature of resultant solution is :
What is the normality of 1.2 M CH_3COOH
What is the pH of solution in which 25.0 mL of 0.1 M NaOH is added to 25 mL of 0.08 M HCl and final solution is diluted to 500 mL?
20 mL of 0.2 M NaOH(aq) solution is mixed with 35 mL of this 0.1 ML NaOH (aq) solution and the resultant solution is diluted to 100 mL. 40 mL of this diluted solution reacted with 10% impure sample of oxalic acid (H_(2)C_(2)O_(4)) The mass of impure is:
An aqueous solution at room temperature contains 0.1 M NH_(4)Cl and 0.01M NH_(4)OH (pK_(b)=5), the pH of the solution is :
A solution of weak acid HA was titrated with base NaOH. The equivalent point was reached when 40 mL. Of 0.1 M NaOH has been added. Now 20 mL of 0.1 M HCl were added to titrated solution, the pH was found to be 5.0 What will be the pH of the solution obtained by mixing 20 mL of 0.2 M NaOH and 20 mL of 0.2 M HA?
What is the pH of 0.1M NaOH solution?
When a 20 mL of 0.08 M weak base BOH is titrated with 0.08 M HCl, the pH of the solution at the end point is 5. What will be the pOH if 10 mL of 0.04 M NaOH is added to the resulting solution? [Given : log 2=0.30 and log 3=0.48]
Calculate the pH of 0.2 M CH_3 COOH (K_a = 1.5 xx 10^-5) .
NARENDRA AWASTHI-IONIC EEQUILIBRIUM-Assertin-Reason Type Questions
