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If 16 g of CH4 and 4 g of H2 are mixed a...

If `16 g `of `CH_4` and 4 g of `H_2` are mixed and kept at 760 mm Hg pressure at `0^@C`, then volume occupied by the mixture would be

A

22.4L

B

44.8 L

C

67.2 L

D

33.6 L

Text Solution

Verified by Experts

The correct Answer is:
C
`n = 1 + 2 = 3 = 3` mole
`therefore ` Volume of 3 mole gas at `NTP = 3 xx 22.4 L`
`V = 67.2 L`
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