The equivalent weight of `MnSO_(4)` is half its molecular weight when it is converted to

Options

A. `Mn_(2)O_(3)`
B. `MnO_(2)`
C. `MnO_(4)^(-)`
D. `MnO_(4)^(2-)`

Answer

C

Explanation

In `MnSO_(4)` oxidation state of Mn = +2. In `Mn_(2)O_(3)`, oxidation state of `Mn = +3`. There is an increase of oxidation state by 1 when `MnSO_(4)` changes to `Mn_(2)O_(3)`. Hence, its equivalent mass is equal to its molar mass
Equilvalent weight `=("Molecular weight")/("Oxidation state")`