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In the following reaction: 3Fe+4H(2)Or...

In the following reaction:
`3Fe+4H_(2)OrarrFe_(3)O_(4)+4H_(2)`, if the atomic weight of iron is `56`, then its equivalent weight will be

A

42

B

21

C

63

D

84

Text Solution

Verified by Experts

The correct Answer is:
B

`3Fe^(0) to Fe_(3)^(8//3) + 8e`
`therefore E = M/(8//3) = (56 xx 3)/8 = 21`
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