In which of the following compounds, an elements exhibits two different oxidation states?

Options

A. `NH_(2)OH`
B. `NH_(4)NO_(3)`
C. `N_(2)H_(4)`
D. `N_(3)H`

Answer

B

Explanation

`NH_(4)NO_(3)` is actually `NH_(4)^(+)` and `NO_(3)^(-)`. It is an ionic compound.
Nitrogen in the two species have different as oxidation no. shown below.
Let, oxidation number of N in `NH_(4)^(+)` is x.
`rArr x + (4 xx 1) = +1`
or `x +4= +1` or `x = -3`
Let, oxidation number of N in `NO_(3)^(-)` is x.
`rArr x +(3 xx -2) =-1`
or `x-6 =-1` or `x = +5`