Reaction of ethene with `Br_(2)` in `C Cl_(4)` given :

Options

A. Bromoethane
B. 1,2-dibromoethane
C. 1,1-Dibromethane
D. 1,1,2-2-Tetrabromoethane

Answer

To solve the problem of the reaction of ethene with bromine in carbon tetrachloride (CCl4), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are ethene (C2H4) and bromine (Br2). Ethene is an alkene with a double bond between the two carbon atoms.

### Step 2: Understand the Reaction Mechanism
The reaction of ethene with bromine is an example of electrophilic addition. In this reaction, the double bond in ethene acts as a nucleophile and attacks the electrophilic bromine molecule.

### Step 3: Formation of the Bromonium Ion
When ethene reacts with bromine, the double bond attacks one of the bromine atoms, leading to the formation of a bromonium ion. This is a three-membered cyclic structure where one bromine atom is positively charged and is bonded to both carbon atoms of the ethene.

### Step 4: Nucleophilic Attack
The bromide ion (Br-) that is released during the formation of the bromonium ion acts as a nucleophile. It can attack one of the carbon atoms in the bromonium ion. Since both carbon atoms are equivalent in this case, the attack can occur at either carbon.

### Step 5: Product Formation
The result of this nucleophilic attack is the formation of 1,2-dibromoethane. This compound has bromine atoms attached to both the first and second carbon atoms of the original ethene.

### Final Product
The final product of the reaction is 1,2-dibromoethane (C2H4Br2).

### Summary of the Reaction
The reaction of ethene with bromine in CCl4 results in the formation of 1,2-dibromoethane.

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