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For H2O TC = 647 K, PC = 218 atm V...

For `H_2O`
`T_C = 647 K`,
`P_C = 218 atm`
`V_C = 0.057 L mol^(-1)`
What is the value of .a. for `H_2O`?

A

`2.12 L^2 atm mol^(-2)`

B

`0.019 L^2 atm mol^(-2)`

C

`8.31 L^2 atm mol^(-2)`

D

`0.082 L^2 atm mol^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
A

`a = 3p_C V_C^2`
`=3 xx 218 xx (0.057)^2`
`= 2.12 L^2 "atm mol"^(-2)`
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