Oxidation number if iodine in `IO_(3)^(-), IO_(4)^(-),KI and I_(2)` respectively are

Options

A. `-1, -1, 0 , +1`
B. `+3, +5, +7, 0`
C. `+5, +7, +1,0`
D. `-1,-5,-1,0`

Answer

C

Explanation

Oxidation state of 1 in `IO_(3)^(-)`
Oxidation state of I in `IO_(4)^(-)`
`x + (-2)4 =-1 rArr x = +7`
Oxidation state of 1 in KI
`+1 +x =0 rArr x =-1`
Oxidation state of 1 in `I_(2), x=0`
Hence, the oxidation number of iodine in `IO_(3)^(-), IO_(4)^(-), KI` and `I_(2)` are respectively `+5, +7, -1` and 0.