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0.52 g of a dibasic acid required 100 mL...

0.52 g of a dibasic acid required 100 mL of 0.2 N NaOH for complete neutralization. The equivalent weight of acid is:

A

26

B

52

C

104

D

156

Text Solution

Verified by Experts

The correct Answer is:
A

`M_(eq)` of acid `=M_(q)` of NaOH
`0.52/E xx 1000 = 100 xx 0.2`
`therefore E =26`
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