The numbe of mole of `MnO_(4)^(-)` required by 1 mole of ferric exalate for oxidation is/are-

Options

A. 0.2
B. 1.2
C. 2.6
D. 5.2

Answer

B

Explanation

`48H^(+) + 6MnO_(4)^(-) + 5Fe_(3)(C_(3)O_(4))_(3) to 6Mn^(2+) + 3CO_(3) + 10Fe^(3+) + 24H_(2)O`
5 moles of ferric oxalate require `MnO_(4)^(-) = 6` moles
1 mole of ferric oxalate require `MnO_(4)^(-) = 6/5 = 1.2`