On strong heating `MgCl_(2).6H_(2)O` the product obtained is

Options

A. `MgCl_(2)`
B. `MgO`
C. `MgCl_(2).2H_(2)O`
D. `MgCl_(2).4H_(2)O`

Explanation

To solve the question regarding the product obtained from the strong heating of `MgCl2.6H2O`, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Compound**: We start with the hydrated form of magnesium chloride, which is `MgCl2.6H2O`. This indicates that there are 6 water molecules associated with each formula unit of magnesium chloride.

2. **Initial Heating**: When `MgCl2.6H2O` is heated, the first step is the removal of the water of crystallization. The heating will lead to the loss of water molecules. The first product formed is `MgCl2.2H2O` after the loss of 4 water molecules.

3. **Further Heating**: If we continue to heat `MgCl2.2H2O`, we will lose the remaining water molecules. The next product formed will be `MgOCl` (Magnesium Oxychloride) along with the release of hydrochloric acid (HCl) gas.

4. **Final Heating**: Upon strong heating, `MgOCl` can decompose further. The final product of this strong heating process will be magnesium oxide (`MgO`), as the chlorine and oxygen are released in the form of HCl and other gases.

5. **Conclusion**: Therefore, after strong heating of `MgCl2.6H2O`, the final product obtained is `MgO` (magnesium oxide).

### Final Answer:
The product obtained from the strong heating of `MgCl2.6H2O` is `MgO` (magnesium oxide).

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