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The ratio of the heights 1.50 m and 75 c...

The ratio of the heights 1.50 m and 75 cm of two persons can be written as

A

`1:50`

B

`1:5`

C

`2:1`

D

`1:2`

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The correct Answer is:
To find the ratio of the heights of two persons, we need to ensure both heights are in the same unit. Let's solve the problem step by step. ### Step-by-Step Solution: 1. **Convert the heights to the same unit**: - The height of the first person is given as 1.50 meters. - The height of the second person is given as 75 cm. - Since 1 meter equals 100 cm, we convert 1.50 meters to centimeters: \[ 1.50 \text{ m} = 1.50 \times 100 \text{ cm} = 150 \text{ cm} \] 2. **Write the heights in centimeters**: - Height of the first person: 150 cm - Height of the second person: 75 cm 3. **Set up the ratio**: - The ratio of the heights can be written as: \[ \text{Ratio} = \frac{\text{Height of first person}}{\text{Height of second person}} = \frac{150 \text{ cm}}{75 \text{ cm}} \] 4. **Simplify the ratio**: - To simplify the ratio, divide both the numerator and the denominator by 75: \[ \frac{150 \text{ cm}}{75 \text{ cm}} = \frac{150 \div 75}{75 \div 75} = \frac{2}{1} \] 5. **Final ratio**: - Therefore, the ratio of the heights of the two persons is: \[ 2:1 \]
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NCERT EXEMPLAR-COMPARING QUANTITIES-THINK AND DISCUSS
  1. The ratio of the heights 1.50 m and 75 cm of two persons can be writte...

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  2. Describe how two ratios can form a proportion.

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  3. Give three ratios equivalent to 12 : 24.

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  4. Explain why the ratios 2 : 4 and 6 :10 do not form a proportion.

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  5. Give an example of two ratios that are proportional and have numerator...

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  6. The speed of a Garden-Snail is 50 meters per hour and that of the Chee...

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  7. Determine the ratios that are nearly equivalent to each of the followi...

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  8. Describe how to find 35% of a number when you know 10% of the number.

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  9. Explain whether a 150% increase or a 150% decrease is possible.

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  10. Compare finding a 20% increase for finding 120% of a number.

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  11. Show Rs. 25 as a part of a 100 rupee note in terms of (1) a reduced fr...

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  12. Explain how you can find a fraction, decimal, or per cent when you hav...

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  13. Show why 5% of a number is less than 1/10 of the number.

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  14. Demonstrate two ways to find 70% of a number.

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  15. Name fractions in simplest form that are the same as 40% and as 250%.

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  16. Compare finding a number when a per cent of the number is known to fin...

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  17. Explain whether a number is greater than or less than 36, if 22 per ce...

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  18. Explain the meaning of each variable in the interest formula.

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  19. Tell what value should be used for time 't' in years when referring to...

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  20. Name the different variables in the simple interest formula.

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  21. Demonstrate that doubling the time while halving the interest rate res...

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