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Arrange in descending order: 2^(2+3),(...

Arrange in descending order:
`2^(2+3),(2^(2))^(3),2xx2^(2),(3^(5))/(3^(2)),3^(2)xx3^(@),2^(3)xx5^(2)`

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Arrange in ascending order: 2^(5),3^(3),2^(3)xx2,(3^(3))^(2),3^(5),4^(@),2^(3)8^(1)

3^(3)-2^(2)xx5=?

(3^(3)xx3^(5)xx2^(3))/(3^(2)xx6)

(2^((1)/(3))xx5^((2)/(3)))/(2^(-(2)/(3))xx5^(-(1)/(3)))

(2/3)^(-2)xx(2/3)^(-5)=(2/3)^(10)

hcf of 3^(3)xx5 and 3^(2)xx5^(2)

(((2)/(3))^(3)xx(-(3)/(4))^(2))/([-(2)/(5)]^(3))

Simplify: ((3^(-2))^(2)xx(5^(2))^(-3)xx(t^(-3))^(2))/((3^(-2))^(5)xx(5^(3))^(-2)xx(t^(-4))^(3))

H.C.F.of 3240,3600 and a third number is 36 and their L.C.M.is 2^(4)xx3^(5)xx5^(2)xx7^(2) .The third number is (a) 2^(2)xx3^(5)xx7^(2)(b)2^(2)xx5^(3)xx7^(2)(c)2^(5)xx5^(2)xx7^(2)(b)2^(3)xx3^(5)xx7^(2)

((3)^(-5)xx5^(-2)xx27^(2/3))/(6^2xx25^(1/2)xx49^(-1/2))