The rate constant for an isomerisation reaction, `A to B` is `4.5 xx 10^(-3)" min"^(-1)`. If the initial concentration of A is 1 M, calculate the rate of reaction after 1 h.

Explanation

`k = 4.5 xx 10^(-3)" min"^(-1) [A_0]=1M, [A] = (1-x)M`
`t=60" s"`
`60 = (2.303)/( 4.5 xx 10^(-3) ) log"" ((1))/((1-x))`
`rArr log"" (1)/( 1-x) = (4.5 xx 10^(-3) xx 60)/( 2.303) = 0.117`
`rArr (1)/(1-x)=" antilog" 0.117 = 1.30 rArr (1)/(130) = 1-x`
`rArr (1-x) = [A] = 0.76M`
Now, rate of reaction `=k [A] = 4.5 xx 10^(-3) xx 0.76`
`= 3.42 xx 10^(-3)" mol L"^(-1)" min"^(-1)`