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Define an expression for the rate consta...

Define an expression for the rate constant of a 1st order reaction. Define half life period. A first order reaction takes 69.3 minutes for 50% completion. How much time will be needed for 80% completion?

Text Solution

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As we know that,
`k = (0.693)/( t_(1//2) ) = (0.693)/(69.3" min" )= 0.01" min"^(-1)` Suppose that `t` be the time taken for 80% completion.
`t= (2.303)/( k) log"" (100)/( 100 - 80) `
`= (2.303)/( 10^(-2)" min"^(-1) ) log 5`
`= 230.3 xx 0.6989" min" = 160.97" min"`
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