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PtCl(4)andNH(3) may form five complexes,...

`PtCl_(4)andNH_(3)` may form five complexes,
` A (PtCl_(4)*6NH_(3)),B(PtCl_(4)*5NH_(3)),C(PtCl_(4)*4NH_(3)),D(PtCl_(4)*3NH_(3))andE(PtCl_(4)*2NH_(3))`. One mole of each A, B, C, D and E reacts with excess of `AgNO_(3)` to yield 4, 3, 2 and 1 mole(s) of AgCl respectively, while E gives, no AgCl. The conductance of their solutions are in the order `AgtBgtCgtDgtE`. On the basis of Werner's theory, write their strucutre and give the total number of ions given by one complex.

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