What happens when KI solution is added to acidified `K_2Cr_2O_7` solution?

Explanation

When Kl solution is added to acidified `K_2Cr_2O_7` solution, it gives `Cr^(3+)` and `I_2` as follows :
`Cr_2O_7^(2-)+14H^++6I^(-)rarr2Cr^(3+)+3I_2+7H_2O`
or `K_2Cr_2O_7+7H_2SO_4+KIrarrunderset"Chromium (III) sulphate"(Cr_2(SO_4)_3)+7H_2O+4K_2SO_4+3I_2`