The correct thermodynamic conditions for the spontaneous reaction at all temperature is

Options

A. `DeltaH lt 0` and `DeltaS lt 0`
B. `Delta H lt 0` and `DeltaS=0`
C. `Delta H gt 0` and `DeltaS lt 0`
D. `Delta H lt 0` and`DeltaS gt 0`

Answer

D

Explanation

For any spontaneous process, `DeltaG= (-ve) and `Delta S= (+ve) that is increase in entropy
So, at `DeltaH lt 0` and `Delta S gt 0` at all temperatures according the reaction will be spontaneous.