If heat of dissocitation of `CHCl_(2)COOH` is 0.7 kcal/mole then `Delta H` for the reaction:
`CHCl_(2)COOH+KOH rarrCHCl_(2)COOK+H_(2)O`

Options

A. `-13` kcal
B. +13 kcal
C. -14.4 kcal
D. -13.7 kcal

Answer

A

Explanation

The required heat released will be (13.7- heat required to dissociate `CHCl_(2)COOH` )= 13.0 kcal
`H^(+) +OH^(-) to H_(2)O (l) " " DeltaH= -13.7 kcal`…(i)
`CHCl_(2)COOH" "CHCl_(2)COO^(-) +H^(+) to DeltaH= 0.7 kcal`. ….(ii)
`CHCl_(2)COOH +OH^(-) to CHCl_(2)COO^(-) +H_(2)O(l)DeltaH=?`
Adding equation (i) and (ii) `DeltaH= -13 kcal`