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The bond dissociation energies ofX(2),Y(...

The bond dissociation energies of`X_(2),Y_(2)andXY` are in the ratio of`1:0.5:1.DeltaH` for the formation of `XY`is `-200kJmol^(-1)`.The bond dissociation energy of `X_(2)`will be

A

`200 kJ mol^(-1)`

B

`100 kJ mol^(-1)`

C

`400 kJ mol^(-1)`

D

`800 kJ mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
The reaction for `Delta_(f)H^(@)(XY)`
`(1)/(2)X_(2)(g) +(1)/(2)Y_(2)(g) to XY(g)`
bond energies of `X_(1), Y_(2)` and XY are x, `(x)/(2)` , x respectively.
`:. DeltaH= ((x)/(2)+(x)/(4))-(x)/(2)=-200`
On solving we get,
`implies (x)/(4)= -200`
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