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A metallic crystal has the bcc type stac...

A metallic crystal has the bcc type stacking pattern. What percentage of volume of this lattice in empty space?

A

0.68

B

0.32

C

0.26

D

0.74

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The correct Answer is:
To solve the problem of finding the percentage of volume of a body-centered cubic (BCC) lattice that is empty space, we can follow these steps: ### Step 1: Understand the BCC Structure In a body-centered cubic (BCC) lattice, there are: - 1 atom at the center of the cube. - 8 corner atoms, each contributing \( \frac{1}{8} \) of an atom to the unit cell. ### Step 2: Calculate the Total Number of Atoms per Unit Cell The total number of atoms \( z \) in a BCC unit cell can be calculated as follows: \[ z = \text{(contribution from corner atoms)} + \text{(contribution from body-centered atom)} = 8 \times \frac{1}{8} + 1 = 2 \] ### Step 3: Calculate the Volume of Atoms in the Unit Cell The volume of a single atom (considered as a sphere) is given by the formula: \[ \text{Volume of one atom} = \frac{4}{3} \pi r^3 \] Thus, the total volume of atoms in the BCC unit cell is: \[ \text{Total volume of atoms} = z \times \text{Volume of one atom} = 2 \times \frac{4}{3} \pi r^3 = \frac{8}{3} \pi r^3 \] ### Step 4: Relate the Radius of the Atom to the Edge Length of the Cube In a BCC structure, the relationship between the radius \( r \) of the atom and the edge length \( a \) of the cube is given by: \[ a = \frac{4r}{\sqrt{3}} \] ### Step 5: Calculate the Volume of the Unit Cell The volume of the cubic unit cell is: \[ \text{Volume of the cube} = a^3 \] Substituting the expression for \( a \): \[ \text{Volume of the cube} = \left(\frac{4r}{\sqrt{3}}\right)^3 = \frac{64r^3}{3\sqrt{3}} \] ### Step 6: Calculate the Packing Fraction The packing fraction (the fraction of the volume occupied by the atoms) can be calculated as: \[ \text{Packing fraction} = \frac{\text{Total volume of atoms}}{\text{Volume of the cube}} = \frac{\frac{8}{3} \pi r^3}{\frac{64r^3}{3\sqrt{3}}} \] Simplifying this gives: \[ \text{Packing fraction} = \frac{8 \pi \sqrt{3}}{64} = \frac{\pi \sqrt{3}}{8} \approx 0.680 \] ### Step 7: Calculate the Percentage of Empty Space The percentage of empty space in the lattice is given by: \[ \text{Empty space percentage} = 100\% - \text{Packing fraction} \times 100\% \] Substituting the packing fraction: \[ \text{Empty space percentage} = 100\% - 68\% = 32\% \] ### Final Answer Thus, the percentage of volume of the BCC lattice that is empty space is **32%**. ---

To solve the problem of finding the percentage of volume of a body-centered cubic (BCC) lattice that is empty space, we can follow these steps: ### Step 1: Understand the BCC Structure In a body-centered cubic (BCC) lattice, there are: - 1 atom at the center of the cube. - 8 corner atoms, each contributing \( \frac{1}{8} \) of an atom to the unit cell. ### Step 2: Calculate the Total Number of Atoms per Unit Cell ...
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