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In an experiment four quantities a,b,c a...

In an experiment four quantities a,b,c and d are measure with percentage error `1% , 2% , 3%`,and `4%` respectively quantity is P is calculate as follow
`P = (a^(3)b^(2))/(cd) %` error in `P` is

A

`4%`

B

`14%`

C

`10%`

D

`7%`

Text Solution

Verified by Experts

The correct Answer is:
B
`P = (a^2b^2)/(cd) implies (DeltaP)/(P) = pm (3 (Delta a)/(a) + 2 (Deltab)/(b) + (Deltac)/(c) + (Delta d)/(d))`
`= p, (3 xx 1 + 2 xx 2 + 3 xx 4) = pm 14%`
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