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If units of length, mass and force are c...

If units of length, mass and force are chosen as fundamental units, the dimensions of time would be :

A

`M^(1//2) L^(-1//2) F^(1//2)`

B

`M^(1//2) L^(1//2) F^(1//2)`

C

`M^(1//2) L^(1//2) F^(-1//2)`

D

`M^1 L^(-1//2) F^(-1//2)`

Text Solution

Verified by Experts

The correct Answer is:
C
`F = M^1L^1 T^(-2)`
`therefore T^2 = (M^1 L^1)/(F)`
`T= M^(1//2) L^(1//2) F^(-1//2)`
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