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If Q = (X^n)/(Y^m) and Delta X is abso...

If ` Q = (X^n)/(Y^m)` and `Delta X ` is absolute error in the measurement of X, `Delta Y` is absolute error in the measurement of Y, then absolute error `Delta Q ` in Q is :

A

`DeltaQ = pm (n (Delta x)/(x) + m (Deltay)/(y))`

B

`DeltaQ = pm (n (Delta x)/(x) + m (Deltay)/(y))Q`

C

`DeltaQ = pm (n (Delta x)/(x) - m (Deltay)/(y))Q`

D

`DeltaQ = pm ((nDelta x)/(x) -(m Deltay)/(y))Q`

Text Solution

Verified by Experts

The correct Answer is:
B

Here , maximum fraction error is :
`(Delta Q)/Q = pm (n (Delta x)/(x) + (m Delta y)/(y)) `
`therefore ` Absolute error in Q, ie.
`Delta Q = pm (n (Delta x)/(x) + (m Delta y)/(y))Q`
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