Dimensional formula of self-inductance i...

Dimensional formula of self-inductance is

`[MLT^(-2) A^(-2)]`

`[ML^(2) T^(-1) A^(-2)]`

`[ML^2 T^(-2) A^(-2)]`

`[ML^2 T^2 A^(-1)]`

Text Solution

Verified by Experts

The correct Answer is:

Induced `emf |epsilon| = L (dI)/(dt)`
where L is the self inductance of `(dI)/(dt)` is the rate of change of current.
`therefore` Dimensional formular of `L = (|epsilon|)/((dI)/(dt))`
`= w/q . (dI)/(dt) = ([ML^2 T^(-2)][T])/([AT][A]) = [ML^2 T^(-2) A^(-2)]`

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The dimensional formula for inductance is

`[ML^2 T^(-2) A^(-2)]`

`[ML^2 TA^(-2)]`

`[ML^2T^(-1)A^(-2)]`

`[ML^2T^(-2)A^(-2)]`

The dimensional formula for conductance is

`[M^(-1) L^(-2) T^3 A^(-2)]`

`[M^1 L^2 T^(-3) A^2]`

`[M^(-1)L^(-2) T^(-3) A^2]`

`[M^(-1)L^(-2)T^3 A^2]`

Unit of self inductance is

`("Newton-second")/("Coulomb"xx"Ampere")`

`("Joule"//"Coulomb"xx"Second")/("Ampere")`

`("Volt"xx"metre")/("Coulomb")`

`("Newton"xx"metre")/("Ampere")`