Taking velocity , time and force as the fundamental quantities , find the dimension of mass .

Options

A. `FTV `
B. `F^(-1)TV `
C. `FTV^(-1)`
D. `FT^(-1)V`

Answer

C

Explanation

`[M] = [F^a T^b V^c]`
`[M^1 L^0 T^0] = [(MLT^(-2))^a (T)^b (LT^(-1))^c]`
Equating dimensions of M,L, and T
`{:(1 = a, 0 = a + c, 0 = - 2a + b + c),(a = 1, c = -1, b = 1):}`
`[M] = F^1 T^1 V^(-1)`