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The frequency f of vibrations of a mass ...

The frequency `f` of vibrations of a mass `m` suspended from a spring of spring constant `k` is given by `f = Cm^(x) k^(y)` , where `C` is a dimensionnless constant. The values of `x and y` are, respectively,

A

`x =1/2 , y = 1/2`

B

`x = -1/2 , y = -1/2`

C

`x = -1/2 , y = 1/2`

D

`x = 1/2 , y = 1/2`

Text Solution

Verified by Experts

The correct Answer is:
C

`n prop cm^x k^y`
`[n] = [ cm^x k^y]`
`[T^(-1)] = [M^x (F/x)^y ]`
`[M^0 L^0 T^(-1)] = [M^x ((MLT^(-2))/(L))y]`
Equating power of M,L and T
`0 = x + y`
`-1 = -2 y " " y = 1/2 , " " x = -1/2`
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