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If Force=(x/density)+C is dimensionally ...

If Force=(x/density)+C is dimensionally correct, the dimension of x are -

A

`MLT^(-2)`

B

`MLT^(-1)`

C

`ML^2 T^(-3)`

D

`M^2 L^(-2) T^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`F = X/("density") + c "then " [X] =` [F density]
`[x] = [MLT^(-2) . ML^(-3)] = [M^2 L^(-2) T^(-2)]`
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