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Given : force = (alpha)/("density" + bet...

Given : force `= (alpha)/("density" + beta^3).` What are the dimensions of `alpha, beta ?`

A

`ML^(-2) T^(-2) , ML^(1//2)`

B

`M^2 L^4 T^(-2), M^(-1//3) L^(-1)`

C

`M^2 L^(-2) T^(-2) , M^(1//3) L^(-1)`

D

`M^2 L^(-2) T^(-2), ML^(-3)`

Text Solution

Verified by Experts

The correct Answer is:
C

`beta^2` = density = `M^2 L^(-3)`
`beta = M^(1//3) L^(-1)`
Also, `alpha = " force" xx " density" `
`= MLT^(-2) xx M^1 L^(-3) = [M^2 L^(-2) T^(-2)]`
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