Given `F = (a//t) + bt^2` where F denotes force and t time. The diamensions of a and b are respectively:

Options

A. `M^0 L^0 T^1 , M^0 L^0 T^(-2)`
B. `M^0 L^1 T^(-2), M^- L^2 T^(-2)`
C. `M^1 L^1 T^(-3), M^1 L^1 T^(-3)`
D. `M^1 L^1 T^(-1), M^2 L^1 T^(-2)`

Answer

C

Explanation

`F = at^(+1) + bt^(+2)`
`[a] = [F/t] = [(MLT^(-2))/(T)] = [MLT^(-3)]`
`[b] = [F/(t^2)] = [(MLT^(-2))/(T^2)] = [MLT^(-4)]`