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A particle move a distance x in time t a...

A particle move a distance `x` in time `t` according to equation `x = (t + 5)^-1`. The acceleration of particle is alphaortional to.

A

`("Velocity")^(2//3)`

B

`("Velocity")^(3//2)`

C

`("Distance")^(2)`

D

`("Distance")^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`x=(1)/(t+5)impliesv=(dx)/(a)=-(1)/((t+5)^(2))`
Acceleration,
`a=(dv)/(dt)=(2)/((t+5)^(2))impliesa prop("velocity")^(1//2)`
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