An `alpha` - particle in a cyclotron changes its velocity from `30` km/s south to `40` km/s west in `10` second what is the magnitude of average acceleration during this time :

Options

A. `5"Km/s"^(2)`
B. `7"Km/s"^(2)`
C. `9"Km/s"^(2)`
D. `11"Km/s"^(2)`

Answer

A

Explanation

`|Deltav|` Magnitude of change in velocity
`=sqrt((30)^(2)+(40)^(2))=sqrt(900+1600)`
`{:(|Deltav|=sqrt(2500)=50"km/s",|a|=(50)/(10)"km/s"^(2),=5"km/s"^(2)):}`