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For a particle moving in a straight line...

For a particle moving in a straight line, the displacement of the particle at time `t` is given by
`S=t^(3)-6t^(2) +3t+7`
What is the velocity of the particle when its acceleration is zero?

A

`3` m/s

B

`-12` m/s

C

`42` m/s

D

`-9` m/s

Text Solution

Verified by Experts

The correct Answer is:
D
`S=t^(3)-6t^(2)+3t+4`
`V=(ds)/(dt)=3t^(2)-12t+3`
`a=(dv)/(dt)=6t-12=0 :. t=2` sec
`v=3(2)^(2)-12xx2+3=12-24+3=-9` m/s
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