A bullet is fired horizontally from a rifle at a distant target.
Ignoring the effect of air resistance,
which of the following is correct ?
Horizontal Acceleration
Vertical Acceleration

Options

A. `10"ms"^(-2)`
`10"ms"^(-2)`
B. `10"ms"^(-2)`
`0"ms"^(-2)`
C. `0"ms"^(-2)`
`10"ms"^(-2)`
D. `0"ms"^(-2)`
`0"ms"^(-2)`

Explanation

To solve the problem regarding the motion of a bullet fired horizontally from a rifle, we need to analyze the forces acting on the bullet and how they affect its acceleration in both horizontal and vertical directions.

### Step-by-Step Solution:

1. **Understanding the Motion**:
- The bullet is fired horizontally, meaning it has an initial horizontal velocity but is subject to gravitational force acting downwards.

2. **Identifying Forces**:
- The only force acting on the bullet in the vertical direction is its weight, which is the product of its mass (m) and the acceleration due to gravity (g).
- The gravitational force can be expressed as \( F = m \cdot g \).

3. **Calculating Vertical Acceleration**:
- Since the only force acting on the bullet in the vertical direction is gravity, the vertical acceleration (a_y) is equal to g.
- Thus, \( a_y = g = 10 \, \text{m/s}^2 \) (downwards).

4. **Calculating Horizontal Acceleration**:
- In the horizontal direction, if we ignore air resistance, there are no forces acting on the bullet after it has been fired.
- Therefore, the horizontal acceleration (a_x) is zero.
- Thus, \( a_x = 0 \, \text{m/s}^2 \).

5. **Conclusion**:
- The horizontal acceleration of the bullet is \( 0 \, \text{m/s}^2 \).
- The vertical acceleration of the bullet is \( 10 \, \text{m/s}^2 \) (downwards).

### Final Answer:
- **Horizontal Acceleration**: \( 0 \, \text{m/s}^2 \)
- **Vertical Acceleration**: \( 10 \, \text{m/s}^2 \) (downwards)