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It was calculated that a shell when fire...

It was calculated that a shell when fired from a gun with a certain velocity and at an angle of elevation `5pi//36` radius should strike a given target. In actual practice it was found that a hill just intervened in the trajectory. At what angle of elevation should the gun be fired to hit the target ?

A

`(5 pi)/(36)"Rad"`

B

`(11 pi)/(36)"Rad"`

C

`(7 pi)/(36)"Rad"`

D

`(13 pi)/(36)"Rad"`

Text Solution

Verified by Experts

The correct Answer is:
D
`theta_(1)=(5 pi)/(36)`
Another angle for same range is the complementary angel `theta_(2)`
Then `theta_(2)` = `(pi)/(2)-((5 pi)/(36))=(18-5)/(36) pi` `theta_(2)=(13)/(36) pi`
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