The equations of motion of a projectile are given by `x=36tm` and `2y=96t-9.8t^(2)m` .The angle of projection is

Options

A. `sin^(-1)(4/5)`
B. `sin^(-1)(3/5)`
C. `sin^(-1)(4/3)`
D. `sin^(-1)(3/4)`

Answer

A

Explanation

`X= 36" t"`
`2y= 96 t -9.8t^(2)`
`(dx)/(dt)=36" "2(dy)/(dt) = 96-19.6" "t`
`at" t"=0" "V_(x)=36" "V_(y)=48`
`tan phi =(48)/(36)=(4/3)`
`sin phi=(4)/(5)`
`phi = sin^(-1)(4/5)`