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A particle is projected with a velocity ...

A particle is projected with a velocity of `25 m//s` at an angle of `30^(@)` with the horizontal . Calculate
(i) The maximum height ,
(ii) time of flight and
(iii) horizontal range .

A

562 m

B

286 m

C

188 m

D

1130 m

Text Solution

Verified by Experts

The correct Answer is:
A

`R=(u^(2) sin 2 theta)/(g)`
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Knowledge Check

  • A particle is projected with velocity of 10m/s at an angle of 15° with horizontal.The horizontal range will be (g = 10m/s^2)

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