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A particle moves in a circular orbit und...

A particle moves in a circular orbit under the action of a central attractive force inversely proportional to the distance `r`. The speed of the particle is

A

Proportional to `r^(2)`

B

Independent of r

C

Proportional to r

D

Proportional to `1//r`

Text Solution

Verified by Experts

The correct Answer is:
B

`F = K (1)/(r)implies(k)/(r) =("mv"^(2))/(r) implies v = sqrt(k/m)`
So mdependent of r
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