An engine pump up 200 kg of water through a height of 20 min 10 second. If the efficiency of the engine is 80% Calculate the power of the engine.

Options

A. 3800 W
B. 5000 W
C. 4900 W
D. 4800 W

Answer

C

Explanation

Output power=`(mgh)/(t)=(200xx9.8xx20)/(10)`=3920 watt
`therefore eta=(P_v)/(P_i)implies=(P_v)/(eta)=(3920xx100)/(80)=4900` watt