A force acting on a particle varies with...

A force acting on a particle varies with the displacement x as `F=ax-bx^2`. Where a=1 N/m and b= 1 N/`m^2`. The work done by this force for the first one meter (F is in newtons, X is in meters) is :

A

`1/6`J

B

`2/6` J

C

`3/6` J

D

None of these

Text Solution

Verified by Experts

The correct Answer is:

A

W=`overset(1)underset(0)(int)Fdx=1/6` J

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