A position dependent force F=7-2x+3x^(2)...

A position dependent force `F=7-2x+3x^(2)` acts on a small body of mass 2 kg and displaced it from `x=0` to `x=5m`. Calculate the work done in joule.

A

70

B

270

C

35

D

135

Text Solution

Verified by Experts

The correct Answer is:

D

W=`overset(5)underset(0)(int)Fdx=7xx5-25xx2/2+125xx3/3=135` J

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