A uniform chain of length 2 m is kept on a table such that a length of 60 cm hangs freely from the edge of the table. The total mass of the chain is 4 kg. What is the work done in pulling the entire chain on the table?

Options

A. 1.713 J
B. 3.174 J
C. 2.750 J
D. 2.500 J

Answer

B

Explanation

x is the fraction of length hanging from the table.
`x=("hanging length")/("total length")=(70)/(300)=0.23`
work done in pulling the chain
`w=(MgLx^2)/(2)=(4xx10xx3xx(0.23)^2)/(2)=3.174` J