A body of mass m is moving in a circle of radius r with a constant speed v, The force on the body is `(mv^(2))/(r )` and is directed towards the centre. What is the work done by the force in moving the body over half the circumference of the circle?

Options

A. `(mv^2)/(pi r^3)`
B. Zero
C. `(mv^2)/(r^2)`
D. `(pir^2)/(mv^2)`

Answer

B

Explanation

Force is perpendicular to displacement hence work done is zero