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Water in a bucket is whirled in a vertic...

Water in a bucket is whirled in a vertical circle with a string attatched to it. The water does not fll down even when thebucket is inverted at the top of its path. We conclude that in this position

A

`mg=(mv^2)/(r)`

B

mg is greater than `(mv^2)/(r)`

C

mg is not greater than `(mv^2)/(r)`

D

mg is not less than `(mv^2)/(r)`

Text Solution

Verified by Experts

The correct Answer is:
C

For water does not fall at topmost point of path that mcans at topmost point N should be greater than or equal to zero.
For N=0, mg=`(mv^2)/(r)`
and for `N gt 0,` mg `lt(mv^2)/(r)`
So that mg is not greater than `(mv^2)/(r)`
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