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A force F=20+10y acts on a particle in y...

A force `F=20+10y` acts on a particle in y-direction where F is in Newton and y in meter. Wrok done by this force to move the particle from `y=0` to `y=1 m` is:

A

30 J

B

5 J

C

25 J

D

20 J

Text Solution

Verified by Experts

The correct Answer is:
C
Work done by variable force is
`w=overset(y_1)underset(y_0)(int)Fdy`
Here,`y_0`=0,`y_1`=1 m
`thereforeW=overset(1)underset(0)(int)(20+10)dy=[20y+5y^2]_0^1=25` J
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