A wire of mass `m` and length `l` is bent in the form of circular ring. The moment of inertia of the ring about its axis is

Options

A. `(Ml)/(4pi ^(2))`
B. `(Ml)/(2pi)`
C. `(Ml)/(4pi)`
D. `(Ml ^(2))/(4pi ^(2))`

Explanation

Wire is bent into circular ring, then radius of wire
`l - 2pi R implies R = (l)/(2pi)`
`therefore` Momentu of inertia of ring about its own axis
`therefore I =MR ^(3) = M ((l )/( 2pi)) ^(2) = ( MI ^(2))/(4pi ^(2))`