The moment of inertia of a thin rod of mass M and length L about an axis perpendicular to the rod at a distance L/4 from one end is

Options

A. `(ML ^(2))/(6)`
B. `(ML ^(2))/(12)`
C. `(7 ML ^(2))/(24)`
D. `(7 ML ^(2))/(48)`

Explanation

Using parallel axis theorem,
`I = I _(CM ) + M ((L)/(4)) ^(2)`
`I = I _(CM ) + M ((L)/(4)) ^(2) = (ML ^(2))/( 12) + ( ML ^(2))/( 16) = ( 7 ML ^(2))/( 48)`