A cylinder is rolling down on a inclined plane of inclination`60^(@)`. What is iths acceleration?

Options

A. `g//3`
B. `g // sqrt3`
C. `sqrt ((2g)/(3))`
D. None of the above

Explanation

For cylinder, `I = 1/2 M R ^(2)`
Also,` 1 = MK ^(2)`
So, `(K ^(2))/( R ^(2)) = (1)/(2) `
SO acceleration,
`a = (g sin theta)/(1 + (K ^(2))/( R ^(2)))= ( g sin 60 ^(@))/( 1 + (1)/(2)) = (g)/( sqrt3)`